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7 months ago
What is the percentage of votes polled in total by all the candidates who lost their security deposits while contesting for constituency A?
Explanatory Answer
We know that candidates who failed to secure more 1/6 th of total valid votes lose their
security deposit.
Let us put the information we have in a table:
• From (1), we know that the 2 nd runner-up in A polled 95000-10000 = 85000 votes
• From (2), we know that everyone in C secured more than (1/ 6)* 600030 = 100005 votes . Also,
the minimum difference between any 2 candidates’ votes was 10,000.
• From (3), let’s assume the total no. of votes polled in D was 100x. Then votes polled by winner =
37,500 + 5x.
Also, we know that candidates who lost their deposit in D together polled 35% votes .
Total votes polled in A = 5,00,000
Total votes polled by top 3 candidates = 2,75,000 + 95,000 + 85,000 = 4,55,000
Votes polled by bottom 7 candidates = 5,00,000 – 4,55,000 = 45,000
We can see that 45,000 is clearly less than 1/6 th of 5,00,000 (83,333) . Hence, all the bottom 7
candidates lost their deposit.
Total % votes polled by them = \(({45000 \over {500000}})*100\) = 9%
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