Ravi is driving at a speed of 40 km/h on a road. Vijay is 54 meters behind Ravi and driving in the same direction as Ravi. Ashok is driving along the same road from the opposite direction at a speed of 50 km/h and is 225 meters away from Ravi. The speed, in km/h, at which Vijay should drive so that all the three cross each other at the same time, is
Explanatory Answer
The speeds of Ravi and Ashok converted to meters per second are 40×5/18=100/9 m/s and 50×5/18=1259 m/s50×518=125/9 m/s respectively.
The relative speed between Ravi and Ashok = 100/9+125/9=225/9 m/s
So they meet exactly after 225/225/9=9 seconds.The distance covered by R in 9 seconds = 100/9×9=100 m.
So, for all three of them to meet at the same time Vijay has to cover 54 + 100 = 154m in 9
Seconds.
∴ The speed of Vijay = 154/9 m/s=154/9×185=61.6kmph
-
No one is replied to this question yet. Be first to reply!