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CAT 2023 Question Paper | CAT Verbal Ability Slot 2

General

10 months ago

Question :

In a rectangle ABCD, AB = 9 cm and BC = 6 cm. P and Q are two points on BC such that the areas of the figures ABP, APQ, and AQCD are in geometric progression. If the area of the figure AQCD is four times the area of triangle ABP, then BP : PQ : QC is

Option C is the correct answer.

Explanatory Answer

Since Ar(ABP),Ar(APQ)&Ar(AQCD) are in GP and Ar(AQCD)=4×Ar(ABP)

Ar(ABP):Ar(APQ):Ar(AQCD)=1:2:4

9x/2:9y/2:27+9z/2=1:2:4

x:y:6+z=1:2:4

y=2x

6+z=4x

x + y + z = 6

x + 2x + 4x – 6 = 6

x = 127127

z = 4x – 6 = 48−427=6748−427=67

∴ x = 2z

Therefore, x:y:z=2:4:1

BP : PQ : QC = 2 : 4 : 1 

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